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机器人学 kinematics2

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For personal use only in study and research; not for

been fixed in space, i.e.

0

1?T

commercial use

i

?

?1

0

0

?T

,

j

?

?0

1

0

?T

,

k

?

?0

2.4 Kinematic Analysis of a Particle in 3D Space

x

,

y

,

z

?

?

the coordinates of P with respect to

O ?

xyz

.



Investigation into the motion of a particle is a simplest yet the most fundamental aspect in kinematics. In this section, we deal with the kinematic equations of a particle P moving in 3D space by

Takingderivatives once and twice with respect time gives the velocity andacceleration of point P

using vector notation. Three coordinate systems will be introduced to describe the curvilinear motion of a particle: They are
?

r?

?

x i

?

y j

?

z k

(1b)

?r?

?

?x?i

?

?y?j

?

?z?k

(1c)

?

Rectangular(Cartesian) Coordinate System (

x

?

y

?

z

)

?

Obviously, this is the form which we are very familiar with.Projectile Problem(A classical problem for particle kinematics)

?

Cylindrical Coordinate System(

r

???

z

)

?

?

Spherical Coordinate System(

r

???

?)

Rectangular (Cartesian) Coordinate System (

x

?

y

?

z

)

An object located at origin of a Cartesian

y

system with its

y

axis upward and

x

axis

v

0

Consider a particle P moving in 3D

k

z

r

P

horizontal as shown, is thrown through the air

with an initial velocity

v

0

and an angle

?0

?0

x

space, in the rectangular coordinate

z

about horizontal at

t

?

0

, determine the

system

O ?

xyz

as shown in the

trajectory function of the object.

figure, its position vector

r

can be

given as

O

j

y

Solution:
Initial conditions

i

,

j

,

r

?

x i

?

y j

?

z k

(1a)

x

i

y

x

k

?

?

the unit vectors of three

Position:

x

0?

0

,

y

0?

0

orthogonal axes. Note that they are constant since all axes have






Velocity:

x ?0

v

0

cos?0

,

y ?0

v

0

sin?0

Acceleration:

?x?

?

0

,

?y?

?

?

g

( g--the gravitational acceleration)

?

?x?

?

0

,

?

x

?

dx

?

cont

?

x

?

v

0cos?

dt


?

?y?

?

?

g

,

?

y
?y 0

d y

?

y?v 0

sin?0

d y

?

t?0

?

gdt

One more integration leads to

Substituting

t ?


x

into the above equation finally results


v

0cos?0


in



Defineer,e?and ezas three orthogonal unit vectors in the

senseof positive r, ?and z

directions,respectively. The position ?r

vector rof Pcanthen be expressed ?e?

bye???e???

e?

r?rer?zez (2a) Oy

er??er

Inorder to achieve the velocity of P, er ??

letus rotate er,e?and ezabout ?er ??

aninfinitesimal time interval
zwith an small angle ??during

?t. ?

Thenthe differentiation of rhas x

theform

Cylindrical Coordinate System (

r

???

z

)

z

r

e

z

e?

?

?

?

e

r

?

r?e

r

?

?

e

z

?

z?e

z

(2b)

In the cylindrical coordinates, the

Since

e

z

keeps unchanged,

e

z

?

0

. While the small changes in

position of a particle P can be

e

r

and

e?

occur as follows

located by

P

Thus

r

-----the radial distance from the

r

z

e

r

z

-axis

e


?

lim

?t?0

?e

r

?

lim

?t?0

??

?t e?

?

??e?

,

?---- the angle from the

x

-axis



O

?


y


r

?t

to the radial line

This will also lead to

z

---the vertical distance from the

x

and thereby

x ?

y

plane.






r?

?

d r

?

lim
??0

?

?

r e

r

?

r??e?

?

z e

z

(2c)





r?

A?

r 1?e?

1 ?1

r e 3 r

3

??3

?1

dt

?


h

O

,???

1

Differentiating Eq.(2c) finally results in the acceleration of P

1

2

??3

?1

r 3?e?

3 ?3

?1

?3

e?1

A

e

r

1

,??

1

?r?

?

?r?e

r

?

r e

r

?

?r??e??r???e??r??e?

??r??e??r???e??r??2

??r????2 r???e???z?e z

?

?

?z?e

??

z

z

(2d)

?

?r?e

?r?

r

?r??e?

r??2?e r

e

r

?z?e

B

3

Velocity Polygon

r 1

?1

?

?

A,

?1

,??

1

,???

1

O

y

1

Sample Problem

r 1

x

Determine

r 3

,

??

3

,

r?3

and

??3

of a RRPR planar mechanism

y

x

e?3

e

r

3

3

as shown provided that

r 1

,

?1

,

r 3

,

?3

,

??

1

and

??1

have been

0

?3

,??

3

,???

3

r 3

,

r 3

,

?r?3

r 3

,

r 3

,

?r?3

A,

B

known.

Solution:

r ?

C

?3

,??

3

,???

3

The polar coordinate system may be used for this problem. The

general formulae 2(a), 2(c) and 2(d) are reduced to

C

y

x

re

r

,

r

?

r r ?

r?e?

?

,

r?

?

??r?

?

r??2

?e

r

?

?r???

?

2

r??

??

VelocityAnalysis

Setp1: Establish the polar coordinate system

r 1

??1

with

e

r

1

and

e?1

being as the unit vectors. The velocity of A in

r 1

?

?1

can




be expressed by

Evaluated in

r 1

?

?1

r

3

finally results in

Since

r 1

is a constant,

r 1?

0

. Thus

Keep in mind that

r 1

is a constant such that

Step 2: Establish another polar coordinate system

r 3

?

?3

with

Evaluated in

r 3

?

?3

e

r

3

and

e?3

being as the unit vectors. The velocity of point A in

The acceleration constraint condition gives

r 3

?

?3

can be expressed by

r 3?e?

3?3

--- the velocity of a fictitious point B on link 3, which is

Projecting the left hand term onto

e?3

and

e

momentarily coincident with the point A.



r e 3 r 3 --- the sliding velocity of A relative to B along the direction

of e r 3 .

Step 3: The velocity of the point A evaluated by using these two

systems SHOULD BE THE SAME. Thus

Projecting

r A?

r 1?e?

1 ?1

onto

e?3

and

e

r

3

, respectively, leads


SphericalCoordinate System

Whena radial distance and two angles are used to specify the

positionof a particle as radar measurement, spherical coordinates

r,?,?can be used as shown in the figure. However, since the

derivationof the acceleration is quite complicated, we only give the

resultshere.

to

r 3?3 2

e

r

3

?r 3???

3

?

2

r 3??

3

?e?3


z



??

3

?r 1

cos

??

??

?

,

r

?r

sin

??

??

?1

r 3


3

1

1


3

1


3

1

??3

?1




r 1?e??

` 1?1

r e 3

r

3

x

e

r

e?

Acceleration Analysis

??3

?1

P

e?

Acceleration analysis can be implemented in the same way.

?1

?3

r

r

y

O

?

r 1??

` 1
2

e

r

1

?

Acceleration Polygon

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